This Sunday will take place All-Russian olympiad for students of 5-8 grades, in the name of Keldysh. Brute force. Hello everyone. Good luck to all the participants! If both players start to eat the same bar simultaneously, Bob leaves it to Alice as a true gentleman. 1, Div. Where to Practice Topic wise for Competitive Programming ? If its odd, then you will be able to skip the turn if it favors you, even if the opponent tries to fight against that. Round 1 as well? [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. Go to file. 2) Editorial. Alice and Bob like games. 42 lines (35 sloc) 1020 Bytes. document.getElementById( "ak_js_1" ).setAttribute( "value", ( new Date() ).getTime() ); Well, to be honest it is not clear why the problem is not solved simply by maintaining two counters for time and two for bars and feeding the chocolate to the player who have smaller current counter of time Hm-m-m Ill try . Raw Blame. How many bars each of the players will consume? Thats the link to my submission: http://codeforces.ru/contest/6/submission/5291991. Faisal's Blog (Algorithm & Datastructure Problems), http://codeforces.com/problemset/problem/6/C, Learn more about bidirectional Unicode characters. Where to Practice Topic wise for Competitive Programming ? During a move, the player eats one or more sweets from her/his side (Alice eats from the left, Bob from the right). For example, if your solution works for 400 ms on judging servers, then the value 800 ms will be displayed and used to determine the verdict. Alice will get all the pieces marked A and Bob will get all the pieces marked B. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. It has created a lot of desperate people who do not actually care about competitive programming but need to be good anyway. The order you need to take the stones is fixed. It is so boring in the summer holiday, isn't it? Pep it up #pepcoding #code #coder #codinglife #programming #coding #java #freeresources #datastrucutres #pepcode #competitive #competitiveprogramming #softwareengineer #engineering #engineer Can someone help me in solving this game theory problem? 2). It is not allowed to eat two chocolate bars at the same time, to leave the bar unfinished and to make pauses. Alice starts to eat chocolate bars one by one from left to right, and Bob from right to left. 1 + Div. For each set of input data print three integers the number of moves in the game and the required values $$$a$$$ and $$$b$$$. In particular, what matters is the ammount of each stone on each mod value. When the player consumes a chocolate bar, he immediately starts with another. 2) Editorial. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them with equal speed). The game ends if all the candies are eaten. And now they are ready to start a new game. Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. So Alice and Bob have invented a new game. The only programming contests Web 2.0 platform. Virtual contest is a way to take part in past contest, as close as possible to participation on time. Alice makes the first move. A tag already exists with the provided branch name. What is optimal way of doing this problem. Codeforces Round #640 (Div. System Crawler 2023-05-16 rickwang 2021-10-11 gonghw 2021-10-08 LBG2019401234 2021-02-23 Please consume this content on nados.pepcoding.com for a richer experience. The order you need to take the stones is fixed. AliceBob : Codeforces Problem 6C. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them with equal speed). Alice will eat candy from left to right, and Bob from right to left. In other words, on a move, a player eats the smallest possible number of candies such that the sum of the sizes of candies eaten on this move is strictly greater than the sum of the sizes of candies that the other player ate on the previous move. You will keep alternating between them after that, and the loser is the one who runs out of stones of the type he wants that turn (you also need to think of the scenario where all of the stones run out, which is really annoying). Hence the solution. On each move, a player counts the total size of candies eaten during the current move. . I did brute force and passed some test cases though. Blog Teams Submissions Contests case3's blog Alice and Bob plays break the node By case3 , history , 2 years ago , Hello everyone. Suppose you choose number 5, the opponent chooses 3 and wins the game, making the total 5+3=8 . 2). https://leetcode.com/problems/stone-game-ix/. The game lasts for k k stages, the stages are numbered from 1 1 to k k. During the i i -th stage, Alice must remove an element from the array that is less than or equal to . The problem statement has recently been changed. I deleted all nodes and then computed cost every time. Thus, we can check the scores of both players if Alice removes the vertex $$$u$$$ at first. Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. Second observation: you can never start with a stone that has value 0, so you will have to pick either one with value 1 or 2. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. Yes, your solution will work (not exactly how you have described, but there is definitely an intuitive iterative implementation). So, obviously at the start iteration isLeft will be false. I am not able to get the discussions /editorial , this problem is very tough . What connected components are there after removing the vertex $$$u$$$? Can someone help me in solving this game theory problem? Then you pick which situation is the one that is better for the first player, because they are going to choose which one the game starts. If the number of stones with value 0 is odd, then the loser is the opposite (because of the third observation). If the number of them is even, then nothing can be done because if you want to skip the turn the opponent can always skip back. Alice can pick rock 'a' times, scissors 'b' times and paper 'c' times. For me, I think better recursively than iteratively. Please Help !!!!!!!!!! Solution: test for picking a stone with value 1 first, then for picking a stone with value 2 first. 2). move 3: Bob ate $$$5$$$ on the previous move, which means Alice must eat $$$6$$$ or more. So, please ask tomorrow. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. First observation: the values of the stones by themselves doesnt matter, what matters is their value mod 3. 2) Editorial. Please Help !!!!!!!!!! https://leetcode.com/problems/stone-game-ix/. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. I am not able to get the discussions /editorial , this problem is very tough . Alice and Bob are playing a game. There are $$$n$$$ candies in a row, they are numbered from left to right from $$$1$$$ to $$$n$$$. Alice eats two candies with the total size of $$$5+9=14$$$ and the sequence of candies becomes $$$[2,6]$$$. After you pick a stone with value 2, you cant pick a stone with value 1, so you will have to pick a stone with value 2, and then you will have to pick a stone with value 1, and them two, and so it goes. Alice and Bob By ayush29azad , history , 21 month (s) ago , Can someone help me in solving this game theory problem? Before contest Codeforces Round 862 (Div. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. If the number of them is even, then nothing can be done because if you want to skip the turn the opponent can always skip back. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them with equal speed). They have placed n chocolate bars in a line. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. From now on when i talk about value im talking about the value mod 3. Each edge connected to this node will vanish. Here, arr is the given array i is the index of the chocolate Alice is consuming, j is the index of the chocolate Bob is consuming, and isLeft determines from which side the function is getting called in the next iteration. Alice and Bob play an interesting and tasty game: they eat candy. The rules are as follows. expert, 1858) Contribution: 0 Friend of: 12 users Last visit: 18 months ago Registered: 4 years ago Blog entries (0) , comments Talks | Send message Oct 2019 Jan 2020 Apr 2020 Jul 2020 Oct 2020 Jan 2021 Apr 2021 Jul 2021 Oct 2021 1200 1400 1600 1900 Alice_and_Bob Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. From now on when i talk about value im talking about the value mod 3. For example, if $$$n=11$$$ and $$$a=[3,1,4,1,5,9,2,6,5,3,5]$$$, then: Print the number of moves in the game and two numbers: The first line contains an integer $$$t$$$ ($$$1 \le t \le 5000$$$) the number of test cases in the input. 2) 16:57:02 Register now . 2) Editorial. 1, Div. So Alice and Bob have invented a new game to play. I am not able to get the discussions /editorial , this problem is very tough . 3) Interesting Facts, Alternate Solution for 1787-G (Colorful Tree Again). Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. 1, Div. When the player consumes a chocolate bar, he immediately starts with another. I am not able to get the discussions /editorial , this problem is very tough . If there are not enough candies to make a move this way, then the player eats up all the remaining candies and the game ends. It is supported only ICPC mode for virtual contests. In particular, what matters is the ammount of each stone on each mod value. Ive tried to implement my solution as I promised seems, the task is even bit simpler than I thought! Can someone help me in solving this game theory problem? When Alice picks any number from 1 to 7 (inclusive both), the opponent wins the game in the next turn by making the total 8 . 4) problem: 1352D Alice, Bob and Candies. Lowe's hiring challenge is still ongoing till midnight today. From now on when i talk about value im talking about the value mod 3. Return the maximum strength he can achieve. Solution: test for picking a stone with value 1 first, then for picking a stone with value 2 first. To adjust the time limit constraint, a solution execution time will be multiplied by 2. If its odd, then you will be able to skip the turn if it favors you, even if the opponent tries to fight against that. Solution Idea: The package for this problem was not updated by the problem writer or Codeforces administration after we've upgraded the judging servers. Alice and Bob play games. Codeforces Clean Code Champions: Nominate Your Favorites! If you need more clearification feel free to ask in the comment. The rules are as follows. Each of them have Ti available hours each day with i = A;B. grote 5371 tail light wiring diagram. How to solve this problem? The only programming contests Web 2.0 platform, Educational Codeforces Round 152 (Rated for Div. Alice will eat candy from left to right, and Bob from right to left. This in turn has increased the number of people with a shitty attitude, including but not limited to cheaters. Codeforces separates its users into 4 divisions by their rating: For Division 1: 1900rating For Division 2: 1600rating1899 For Division 3: 1400rating1599 For Division 4: rating1399 Given a rating, print in which division the rating belongs. The first line contains an integer $$$n$$$ ($$$1 \le n \le 1000$$$) the number of candies. I participated in the lowe's coding round and there was this question I was not able to solve completely. [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. If no connected component left, alice gets 0. How many bars each of the players will consume? I did this with DFS and max heap. So Alice and Bob have invented a new game to play. The order you need to take the stones is fixed. 1, Div. 3)!!! Input: K = 7, N = 50 Output: Alice Solution: test for picking a stone with value 1 first, then for picking a stone with value 2 first. We have found the sizes of all these components, so we can calculate the value of the largest one, give it to Bob and give all other vertices to Alice. Codeforces Clean Code Champions: Nominate Your Favorites! Im sorry I do not know how to paste code here. 2022 Woodward Dream Cruise. I am not able to get the discussions /editorial , this problem is very tough . 1 + Div. 3) Interesting Facts, Alternate Solution for 1787-G (Colorful Tree Again). So, they have to stick to something similar to competitive programming. Educational Codeforces Round 152 (Rated for Div. There are n pieces, and the i -th piece has a strength pi. "/> art malik true lies. 1 + Div. Codeforces. move 6 (the last): Alice ate $$$14$$$ on the previous move, which means Bob must eat $$$15$$$ or more. [Screencast] Somehow getting top 5 in Codeforces Round 888 (Div. Codeforces Round 887 (Div 1, Div 2) Tutorial, [GYM] HIAST Collegiate Programming Contest 2023, Codeforces Round #884 (Div. CodeForces - 347C Alice and Bob. Each test case consists of two lines. In particular, what matters is the ammount of each stone on each mod value. It is necessary to solve the questions while watching videos, nados.pepcoding.com enables that.NADOS also enables doubt support, career opportunities and contests besides free of charge content for learning. The process consists of moves. If its odd, then you will be able to skip the turn if it favors you, even if the opponent tries to fight against that. The rules are as follows. Each node has some sweetness value that will be given to us. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"A and B and Compilation Errors.cpp","path":"A and B and Compilation Errors.cpp","contentType . It has n nodes and m edges. Alice starts to eat chocolate bars one by one from left to right, and Bob from right to left. Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. isLeft also gives priority to Alice over Bob if both attampt to eat the same chocolate. Third observation: stones with value 0 essentially skip the turn. They have an array of positive integers a a of size n n. Before starting the game, Alice chooses an integer k 0 k 0. This problem can be easily solved using properties of deque,below is the implementation of the same::: The only programming contests Web 2.0 platform, Educational Codeforces Round 152 (Rated for Div. During the first move, she will eat $$$1$$$ candy (its size is $$$a_1$$$). 1 + Div. codeforces / 6 / C / alice-bob-and-chocolate. Never use someone else's code, read the tutorials or communicate with other person during a virtual contest. The problem says, You are given a connected undirected graph. Input The first line of the input contains an integer t (1t104) the number of testcases. 3) Interesting Facts, Codeforces, Alternate Solution for 1787-G (Colorful Tree Again). Counters are pointers to next bar which will be eaten by any of players. move 4: Alice ate $$$6$$$ on the previous move, which means Bob must eat $$$7$$$ or more. . Your email address will not be published. Input: number of test cases then n, m and then sweetness of each node and then the edges. They are not trying to minimize each other' score. Trying to solve an old Topcoder TCO06 problem, Invitation to Codeforces Round 887 (Div. You will keep alternating between them after that, and the loser is the one who runs out of stones of the type he wants that turn (you also need to think of the scenario where all of the stones run out, which is really annoying). The size of the $$$i$$$-th candy is $$$a_i$$$. Second observation: you can never start with a stone that has value 0, so you will have to pick either one with value 1 or 2. Blog Teams Submissions Contests Ambuj123's blog Codeforces Round #640 (Div. Input If its odd, then you will be able to skip the turn if it favors you, even if the opponent tries to fight against that. Given Alice's initial split into two teams, help Bob determine an optimal strategy. It is necessary to solve the questions while watching videos, nados.pepcoding.com. First observation: the values of the stones by themselves doesnt matter, what matters is their value mod 3. During each move, either Alice or Bob (the player whose turn is the current) can choose two distinct integers x and y from the set, such that the set doesn't contain their absolute . 3) Interesting Facts, Alternate Solution for 1787-G (Colorful Tree Again). I tried to construct a spanning tree and also strongly connected components but couldn't understand. Can you explain exactly why you think so ? It is supported only ICPC mode for virtual contests. Alice moves first and she may break a node. If the number of stones with value 0 is odd, then the loser is the opposite (because of the third observation). jli505 . 2) flamestorm April Fools Day Contest 2023 . Can you please elaborate further because my dfs gave me TLE. The strength of a player is then the sum of strengths of the pieces in the group. C. Number Game. move 2: Alice ate $$$3$$$ on the previous move, which means Bob must eat $$$4$$$ or more. This contest is prepared by Moscow Olympiad Scientific Committee that you may know by Moscow Team Olympiad, Moscow Olympiad for Young Students, Moscow Open Olympiad in Informatics (rounds 327, 342, 345, 376, 401, 433, 441, 466, 469, 507, 516, 541, 545, 567 . The way to split up game pieces is split into several steps: First, Alice will split the pieces into two different groups A and B. It is a kind of greedy algorithm I think. 1 + Div. 2), [GYM] The 2023 Damascus University Collegiate Programming Contest, Codeforces Round 888 (Div. Never use someone else's code, read the tutorials or communicate with other person during a virtual contest. Required fields are marked *. Explanation: There is no way for Alice to win the game. Codeforces Clean Code Champions: Nominate Your Favorites! The order you need to take the stones is fixed. They have placed n chocolate bars in a line. This video is part of the series to impart industry-level web development and programming skills in the community. I participated in the lowe's coding round and there was this question I was not able to solve completely. You will keep alternating between them after that, and the loser is the one who runs out of stones of the type he wants that turn (you also need to think of the scenario where all of the stones run out, which is really annoying). Please Help !!!!!!!!!! You have explained why these companies do this, but this is not at all a refutation of "hiring challenges are destroying competitive programming". 2). Title Alice and Bob are playing the game, giving you n numbers, the size of each number is a i a_i a i , And then Alice goes first, each step is to choose two numbers from the n numbers u u u v v v Do poor u v |u-v| u v , If this number does not exist then put u v |u-v| u v Fill in this sequence, otherwise the person loses. A. Alice and Bob time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output It is so boring in the summer holiday, isn't it? The rules are as follows. move 5: Bob ate $$$8$$$ on the previous move, which means Alice must eat $$$9$$$ or more. 2) Editorial. In every vertex $$$v$$$, store the total sweetness value of the subtree of that vertex, call that value $$$\mathrm{sub}[v]$$$. Although, in terms of time and space complexity, it would be the same. Space complexity could not be reduced because we need to store the whole array to process it from the end otherwise my solution would be O(1). Alice_and_Bob - Codeforces Submissions Expert Alice_and_Bob Contest rating: 1724 (max. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"100514Q - Peace of bzjd.cpp","path":"100514Q - Peace of bzjd.cpp","contentType":"file . For every child $$$v$$$ of $$$u$$$ such that there is no back-edge from a descendant of $$$v$$$ to a proper ancestor of $$$u$$$, there will be a component with total sweetness value $$$\mathrm{sub}[v]$$$. In the following, I'll denote as $$$\mathrm{sw}[u]$$$ the sweetness value of $$$u$$$. 4) D. Alice, Bob and Candies 3)!!! I tried to solve the problem recursively. Problem Link : https://leetcode.com/problems/stone-game-ix/ -12 ayush29azad 21 month (s) ago 1 Comments (1) Write comment? The only programming contests Web 2.0 platform. https://leetcode.com/problems/stone-game-ix/. either Alice or Bob (the player whose turn is the current) can choose two distinct integers x and y from the set, such that the set doesn't contain their absolute difference . Codeforces Clean Code Champions: Nominate Your Favorites! The They get a set of n distinct integers. Bob eats two candies with the total size of $$$3+5=8$$$ and the sequence of candies becomes $$$[5,9,2,6]$$$.
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